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2.2.3.17.9 TreeNode::FindNodeByAttribute
Contents
Description
Find a node from a tree by the AttributeName with matching integer value.
Find a node from a tree by the AttributeName with matching string value.
Syntax
TreeNode FindNodeByAttribute( LPCSTR AttributeName, int nVal, BOOL bRecursive = TRUE )
TreeNode FindNodeByAttribute( LPCSTR AttributeName, LPCSTR lpcszValue, BOOL bRecursive = TRUE, BOOL bCaseSensitive = FALSE )
Parameters
- AttributeName
- [input] String representing attribute name of the node whose integer value needs to be compared
- nVal
- [input] the value to compare with
- bRecursive
- [input] true, go through all the tree nodes; false, just go through the Children
- AttributeName
- [input] String representing attribute name of the node whose string value needs to be compared
- lpcszValue
- [input] the value to compare with
- bRecursive
- [input] true, go through all the tree nodes; false, just go through the Children
- bCaseSensitive
- [input] true will take care of lpcszValue's case; else false
Return
The first node which has an attribute AttributeName name with matching value.
The first node which has an attribute AttributeName name with matching string value.
Examples
EX1
#define ATTRIB_NAME "AttribID" void TreeNode_FindNodeByAttribute_ex1() { Tree tr; TreeNode tn1, tn2, tn3; tn2 = tr.AddTextNode("abc", "node2", 2); tn2.SetAttribute(ATTRIB_NAME, 2); tn3 = tn2.AddTextNode("efg", "node3", 3); //tn3 is added to tn2 as its child tn3.SetAttribute(ATTRIB_NAME, 3); tn1 = tn2.FindNodeByAttribute(ATTRIB_NAME, 3); //now tn1 is equal to tn3 out_tree(tn1); }
EX2
#define ATTRIB_NAME "AttribID" void TreeNode_FindNodeByAttribute_ex2() { Tree tr; TreeNode tn1, tn2, tn3; tn2 = tr.AddTextNode("abc", "node2", 2); tn2.SetAttribute(ATTRIB_NAME, "Hello"); tn3 = tn2.AddTextNode("efg", "node3", 3); //tn3 is added to tn2 as its child tn3.SetAttribute(ATTRIB_NAME, "Hi"); tn1 = tn2.FindNodeByAttribute(ATTRIB_NAME, "Hi"); //now tn1 is equal to tn3 out_tree(tn1); }
Remark
See Also
Header to Include
origin.h